User talk:Bubba73

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DeadeyeDave73,"meprabot@gmail"You sure do get to see a lot of American history Bubba73.I sure would've liked to see the guidestones w/ya b4 their demise.Sure would like to know what you think about things!?"><"

I don't have much of an opinion about them. After they were demolished, they said that they were going to rebuild them exactly as before, but I haven't heard any more about it. Bubba73 ^{You talkin' to me?} 21:31, 2 June 2025 (UTC)[reply]

Magic Squares

Hi Bubba73,

I know you all don't want to put this on the Magic Squares Wiki Page because it is original research. I still think it is sort of gray area that falls in the routine math exception, but, whatever... All I did was solve them using standard routine algebra, and it is very easy to doublecheck whether the results are correct or not. In any case, I would still like someone interested in Magic Squares to at least have a look. I notice that we have similar backgrounds (math & physics). John

Method of algebra

Magic squares can be generally solved by assigning variables to each cell and doing the algebra.

1x1 Magic Square, with Magic Constant=1M

This square is trivally magic, since it is a single number. It can be a "normal" magic square by setting M=1, so that the magic constant = (1+1)/2*(1/1) = 1.

M 2x2 Magic Square, with Magic Constant=2M This square is not really considered magic, since all entries are the same number. M M M M 3x3 Magic Square, with Magic Constant=3M This square is the first non-trivial magic square. It can be a "normal" magic square by setting M=5, so that the magic constant = (1+9)/2*(9/3) = 15, and setting the other variables appropriately, ex. a=4, b=9. a b 3M-a-b 4M-2a-b M -2M+2a+b -M+a+b 2M-b 2M-a 4x4 Magic Square, with Magic Constant=4M This particular algebraic solution is also panmagic and most perfect. It can be a "normal" magic square by setting M=8.5, so that the magic constant = (1+16)/2*(16/4) = 34, and setting the other variables appropriately, ex. a=4, b=14, e=5, g=8. a b a+e-g 4M-2a-b-e+g e 4M-a-b-e g a+b-g 2M-a-e+g -2M+2a+b+e-g 2M-a 2M-b 2M-g 2M-a-b+g 2M-e -2M+a+b+e 5x5 Magic Square, with Magic Constant=5M This particular algebraic solution is also panmagic. It can be a "normal" magic square by setting M=13, so that the magic constant = (1+25)/2*(25/5) = 65, and setting the other variables appropriately, ex. a=20,b=8,c=21,d=14,g=4. a b c d 5M-a-b-c-d 3M-a-b g 3M-b-d M+b-c+d-g -2M+a+b+c 4M-a-c-g -M+a+b+d-g M 3M-a-b-d+g -2M+a+c+g M-d+g M-b+c-d+g -M+b+d 2M-g 2M-c+d-g -3M+a+b+c+d 5M-a-b-c-g 2M-c -M+a+c-d+g 2M-a 6x6 Magic Square, with Magic Constant=6M This particular algebraic solution is also panmagic, which means that it cannot be "normal" (having consequtive number from 1..36) A "normal" 6x6 magic square has a magic constant = (1+36)/2*(36/6) = 111. a b -a-b+3M 2M-s 2M-t -M+s+t g h -g-h+3M j 2M-z -j+M+z -a-g+3M -b-h+3M a+b+g+h-3M -j+M+s -M+t+z j+3M-s-t-z s t 3M-s-t -a+2M -b+2M a+b-M -j+2M z j+M-z -g+2M -h+2M g+h-M j+M-s 3M-t-z -j-M+s+t+z a+g-M b+h-M -a-b-g-h+5M 12.188.175.154 (talk) 14:47, 19 May 2025 (UTC)[reply] Dixieland I posted a comment on Talk:Confederate States of America that may interest you. I'll send this same message to [[User talk: BlackAfrican2006]] and you two can fight it out if you wish. Maurice Magnus (talk) 21:17, 21 June 2025 (UTC)[reply] Electricity in rockets This question in the Sci ref desk looks like it could be in your wheelhouse: [1] ←Baseball Bugs ^What's up, Doc? carrots→ 16:28, 5 August 2025 (UTC)[reply]